What is the answer of 1 and 2?
Answers
VI Solve the following problems :
1) 5929 students are seated in an auditorium. There are as many rows as there are students in each row. How many rows are there?
7|5929
Answer :-
7|5929
7|847
11|121
11|11
|1
7 × 7 × 11 × 11 = 5929
√5929 = √[ ( 7 × 7 ) × ( 11 × 11 ) ]
= √[ 49 × 121 ]
= 7 × 11 = 77
∴ There are 77 rows in the auditorium.
___________________________
2) The sides of a rectanglular field are 44 m and 99 m. Find the side of the square field of equal area. [Hint: To start, calculate the area of the rectangle. Then, find the square root of the value thus obtained.]
Answer :-
We know that,
- Area Of Rectangle = Length × Breadth
Here,
- Length = 99 m
- Breadth = 44 m
- Area Of Rectangle = Length × Breadth
- Area Of Rectangle = 99 × 44
- Area Of Rectangle = 4356
Area Of Rectangle = 4356 m²
We know that,
- Area Of Square = Area Of Rectangle
- Area Of Square = 4356 m²
We know that,
- Area Of Square = Side²
- 4356 = Side²
- Side = √4356
- Side = 66
Side = 66 m
→ ANSWER :
VI Solve the following problems :
1) 5929 students are seated in an auditorium. There are as many rows as there are students in each row. How many rows are there?
7|5929
Answer :-
7|5929
7|847
11|121
11|11
|1
7 × 7 × 11 × 11 = 5929
√5929 = √[ ( 7 × 7 ) × ( 11 × 11 ) ]
= √[ 49 × 121 ]
= 7 × 11 = 77
∴ There are 77 rows in the auditorium.
___________________________
2) The sides of a rectanglular field are 44 m and 99 m. Find the side of the square field of equal area. [Hint: To start, calculate the area of the rectangle. Then, find the square root of the value thus obtained.]
Answer :-
We know that,
Area Of Rectangle = Length × Breadth
Here,
Length = 99 m
Breadth = 44 m
Area Of Rectangle = Length × Breadth
Area Of Rectangle = 99 × 44
Area Of Rectangle = 4356
Area Of Rectangle = 4356 m²
We know that,
Area Of Square = Area Of Rectangle
Area Of Square = 4356 m²
We know that,
Area Of Square = Side²
4356 = Side²
Side = √4356
Side = 66
Side = 66 m
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