What is the answer of
k³+6k²+9k+4??
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DONE BY USING VANISHING METHOD
Let f(k)=k³+6k²+9k+4
then, f(-1)= (-1)³+6×(-1)²+9×(-1)+4
= (-1)+6-9+4
= 5-5
=0
Since f(-1)=0 therefore (k+1) is a factor of f(k)
therefore, k³+6k²+9k+4
=k³+k²+5k²+5k+4k+4
=k²(k+1)+5k(k+1)+4(k+1)
=(k+1) (k²+5k+4)
the answer is (k+1) (k²+5k+4).
Let f(k)=k³+6k²+9k+4
then, f(-1)= (-1)³+6×(-1)²+9×(-1)+4
= (-1)+6-9+4
= 5-5
=0
Since f(-1)=0 therefore (k+1) is a factor of f(k)
therefore, k³+6k²+9k+4
=k³+k²+5k²+5k+4k+4
=k²(k+1)+5k(k+1)+4(k+1)
=(k+1) (k²+5k+4)
the answer is (k+1) (k²+5k+4).
sksukhwinder56p69c5w:
Thank you so much
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