Question

What is the answer of no.13.Please tell me in full statement​

Answer 1

SOLUTION:-

Given:

The sides of a triangle are in the ratio 2:3:4. If the shortest side measures 6cm.

To find:

Find the perimeter of the ∆.

Solution:

Let the side of a ∆ be x

So,

⚫2x

⚫3x

⚫4x

Shortest side = 2x

Therefore,

=) 2x= 6cm

=) x= 6/2

=) x= 3cm

Now,

Perimeter of triangle= side+side+side

1st side, 2x= 2×3= 6cm

2nd side,3x= 3×3= 9cm

3rd side, 4x= 4×3= 12cm

Perimeter

=) 6cm + 9cm + 12cm

=) 27cm

Thus,

Perimeter of ∆ is 27cm.

Hope it helps ☺️

Answer 2

➡️ SOLUTION

GIVEN :-

The ratio of the sides of the triangle, i.e. 2:3:4....

LET US ASSUME THAT :-

The sides of the triangle be 2x, 3x and 4x...

ALSO IT IS GIVEN THAT :-

The shortest side measures 6 cm

AND WE KNOW that the shortest side which we assumed was 2x,

simply, ACCORDING TO THE CONDITION :-

2x = 6

=> x = 3.......

NOW WE HAVE ALL OTHER SIDES ALSO, THEY ARE AS FOLLOWS :-

first one = 2x = 2 × 3 = 6 cm

Second one = 3x = 3 × 3 = 9 cm

Third one = 4x = 4 × 3 = 12 cm

MAIN PART

TO FIND THE PARAMETER OF THE TRIANGLE :-

As we know, parameter of triangle = sum of all the sides...

NOW,

PARAMETER OF THIS TRIANGLE = 6 cm + 9cm + 12 cm

= 27 cm ANSWER...

Which is the required parameter of the triangle.

HOPE IT HELPS