Question

what is the answer of question maths​

Answer 1

Answer:

Factorize it to get the answer kindly see the attachment.

The correct answer is option B)

Answer 2

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QuestioN :

$\sf \begin{array} {c} \rightsquigarrow\sf\:the \: \: roots \: \: of \: \: \sf\sqrt{3} {x}^{2} + 10x - 8 \sqrt{3} = 0 \: \: are \underline{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: } \end{array}$

$\circ \sf \: \: \: \: 2 \sqrt{3} \: , \: 4 \sqrt{3} \\ \\ \circ \: \sf \: \frac{2}{ \sqrt{3} } \: , \: - 4 \sqrt{3} \\ \\ \: \circ \: \sf \: - \frac{2}{ \sqrt{3} } \: , \: - \frac{4}{ \sqrt{3} } \\ \\ \: \: \circ \sf \: - 2 \sqrt{3} \: , \: - 4 \sqrt{3}$

SolutioN :

We know Shridhar Acharya formula,

$\: \: \: \: \: \: \: \: \: \boxed{ \tt{ x = \frac{ - b \pm \sqrt{ {( b)}^{2} - 4ac } }{2a} }}$

Substituting values,

$\sf \implies \: x = \frac{ - 10 \pm \: \sqrt{ {(10)}^{2} - 4 \times \sqrt{3} \times ( - 8 \sqrt{3}) } }{2 \sqrt{3} }$

$\sf \implies \: x = \frac{ - 10}{2 \sqrt{3} } \pm \: \frac{14}{2 \sqrt{3} }$

$\sf \therefore \: \: \: \: \: \: { \underline{ \boxed{ \sf{ \: x = \frac{ 2}{\sqrt{3} } \: \: \: \: \: \: \: \: \: \: \: \: \: \: ; \: \: \: \: \: \: \: \: x = - 4 \sqrt{3} }}}}$

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