what is the answer of the following,pliz give steps,thank u
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1. angle A = angle D ( alternate angles )
AO = OD ( given )
angle B = angle C ( alternate angles )
by A.S.A congruency ∆AOB congruent to ∆DOC
2. By C.p.c.t.c OB=OC ; so O is the mid point of BC
AO = OD ( given )
angle B = angle C ( alternate angles )
by A.S.A congruency ∆AOB congruent to ∆DOC
2. By C.p.c.t.c OB=OC ; so O is the mid point of BC
saptarshi57:
thank u for helping
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