Math, asked by neildaripa, 11 months ago

what is the answer of this​

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Answered by Anonymous
5

 \huge \red{ \underline{ \underline{QUESTION \:  - }}}

 \large {=  >  { (2x \:  -  \frac{1}{2x}) }^ {2} - (2x -  \frac{1}{2x} )(2x +  \frac{1}{2x} )}

 \huge \pink{ \underline{ \underline{SOLUTION \:  - }}}

\large {=  >  { (2x \:  -  \frac{1}{2x}) }^ {2} - (2x -  \frac{1}{2x} )(2x +  \frac{1}{2x} )} \:

TAKING COMMON :-

  \large { =  > (2x -  \frac{1}{2x} )  \{2x -  \frac{1}{2x} - 2x \:  -  \frac{1}{2x}  \}}

\large {=  > (2x -  \frac{1}{2x}) ( \frac{ - 1}{2x}  -  \frac{  1}{2x} )}

\large {=  > (2x -  \frac{1}{2x}) ( \frac{  2}{2x} )}

\large {=  > (2x  \times  \frac{1}{x} ) - ( \frac{1}{2x}   \times \frac{1}{x} )}

\large {=  &gt; 2 -  \frac{1}{2  {x}^{2} } } \\  </p><p> \\  \large {=  &gt; \frac{4 {x}^{2} - 1 }{2 {x}^{2} }}

 \huge \red{ \mathfrak{ \bold{ \ \fbox{thank \: u \:}}}}

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