what is the answer of this problem
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⭐⭐Here is your answer⭐⭐
Hence, Area of Trapezium= Area of Parallelogram+Area of ∆.
Area of ∆= √s(s-a)(s-b)(s-c)
Here, S is the half perimeter.
S= 14+15+13= 42/2 = 21
=> √21(21-14)(21-15)(21-13)
=> √21x7x6x8
=> √ 7056
=> 84 cm²
Area of ∆= 1/2xbxh
=> 84cm²= 1/2x14xh
=> 84/7 = h
=> 12cm = h
Area of parallelogram= bxh
Area of parallelogram= 11x12 = 132cm²
Area of Trapezium= Area of Parallelogram+ Area of ∆.
Area of Trapezium= (132+84) cm²
Area of Trapezium= 216cm²
⭐⭐Be Brainly⭐⭐
Hence, Area of Trapezium= Area of Parallelogram+Area of ∆.
Area of ∆= √s(s-a)(s-b)(s-c)
Here, S is the half perimeter.
S= 14+15+13= 42/2 = 21
=> √21(21-14)(21-15)(21-13)
=> √21x7x6x8
=> √ 7056
=> 84 cm²
Area of ∆= 1/2xbxh
=> 84cm²= 1/2x14xh
=> 84/7 = h
=> 12cm = h
Area of parallelogram= bxh
Area of parallelogram= 11x12 = 132cm²
Area of Trapezium= Area of Parallelogram+ Area of ∆.
Area of Trapezium= (132+84) cm²
Area of Trapezium= 216cm²
⭐⭐Be Brainly⭐⭐
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216 m^2 will be the area the parallelogram
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