what is the answer of this question?
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Answered by
1
let theta= x
sin^2x + cos^2x
= (20/29)^2 + (21/29)^2
=400/841+ 441/841
=841/841=1
here is the answer
thank-you
sin^2x + cos^2x
= (20/29)^2 + (21/29)^2
=400/841+ 441/841
=841/841=1
here is the answer
thank-you
Answered by
0
(20^2/29^2)+(21^2+29^2)=400/841+441/841=0.99
abhaygoel71:
how you found 0.99?
400/841=0.47,441/841=0.52=>0.47+0.52=0.99
well.... it can be solved by simple rule for adding fractions dear
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