what is the answer of this question.
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Cos^-1 (1/x) = θ,
1/x = cos θ
Then tan θ = sq. root (x^2- 1) (using Pythagoras) tan = opposite / adjacent
So tan θ = sq. root (x^2- 1) / 1
Option (B) is correct
afaiz8738:
thnxxx
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