Chemistry, asked by surbhi933, 1 year ago

what is the answer of this question

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Answered by Yatinkhandelwal17
1
the energy associated......
by this we have value of energy for E1=-2.17*10-18

so by formula E=E1*z^2/n^2

we get (here z= atomic no.)
and n=no. of orbit

so by putting value of E1 and n=5

we get E=8.68*10-20

surbhi933: thnkyu
Yatinkhandelwal17: your welcome
Answered by savio86
1
the energy associated.. by this we have value of energy for E1--2.17"10-18

so by formula E=E1*z^2/n^2

we get (here z atomic no.) and n=no of orbit

so by putting value of E1 and n=5

we get E- 86.8*10-20

savio86: welcome
savio86: ;-)
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