what is the answer of this question
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sum of all internal angles = 360°
since angles are in ap
therefore first is 45° and let common diff be d
so (( 2 * 45 + 3*d )/2)*4 = 360°
3d = 90°
or, d = 30°
therefore the angles are 45° , 75° ,105° ,145°
i) 105°
But there seems to be a couple of contradictions
i) 45 ° is not mentioned to be the smallest angle
ii) Sum of opposite angles is not equal to 180 which is a property of a cyclic quadrilateral.
iii) If I were to avoid contradiction ii) one of the angles then would be 0°
since angles are in ap
therefore first is 45° and let common diff be d
so (( 2 * 45 + 3*d )/2)*4 = 360°
3d = 90°
or, d = 30°
therefore the angles are 45° , 75° ,105° ,145°
i) 105°
But there seems to be a couple of contradictions
i) 45 ° is not mentioned to be the smallest angle
ii) Sum of opposite angles is not equal to 180 which is a property of a cyclic quadrilateral.
iii) If I were to avoid contradiction ii) one of the angles then would be 0°
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