Question

what is the answer please!​

Answer 1

Question

Find the heat energy developed in the 50Ω resistor, when 2A current passing through it for 5s.

Answer

Given :

Resistance = 50Ω

Current produced = 2A

Time taken = 5s

To find :

The heat energy developed

Solution :

Using joules law of heating that is,

The heat produced in a wire is directly proportional to

• square of current (I²)
• resistance of wire (R)
• time (t) for which current is passed.

In order words,

H = I²Rt

where,

• H denotes Heat produced.
• I denotes current.
• R denotes resistance.
• t denotes time$.$

substituting all the given values in the formula,

➠ H = l²Rt

➠ H = (2)²(50)(5)

➠ H = (4)(50)(5)

➠ H = 1000J

➠ H = 1KJ

thus, the heat developed is 1 kilojoule

Hence, option (a) is correct.

Answer 2

GiveN :-

• Resistance = 50 Ω

• Current passed = 2 A

• Time = 5 s

To FinD :-

• Heat energy developed

SolutioN :-

Heat energy produced is

$: \implies \boxed{\bf Heat = I^2RT} \\ \\: \implies \sf H = {2}^{2} \times 50 \times 5 \\ \\: \implies \sf H = 4 \times 250 \\ \\: \implies \boxed{ \sf H = 1000 \: j}$

1000 joule = 1 KJ

$\large\therefore\: \underline { \green{\bf1KJ \: heat \: is \: developed}}$