Question

what is the answer to (2²⁰ ÷ 2¹⁵)​

Answer 1

Step by step explanation

$\sf{ = ( {2}^{20} \div {2}^{15} )}$

$\sf{ = ( {2}^{20 - 15} )}$

$\sf{ = ( {2}^{5} )}$

$\sf{ = 32}$

Laws of exponents

$\sf {a}^{m} \times {a}^{n} = {a}^{m + n} \: \: \: \: \: \: \: \: \: \: \sf {a}^{m} \div {a}^{n} = {a}^{m - n} \\ \sf{( {a}^{m} ) ^{n} = {a}^{mn} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: a {}^{m} \times {n}^{m} = (ab) ^{m} } \\ \sf{a}^{0} = 1 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: {\frac{ {a}^{m} }{ {b}^{m} }= \left( \frac{a}{b} \right) ^{m} }$

Answer 2

$\sf \pmb{Answer :}$

$\sf{ = ( {2}^{20} \div {2}^{15} )}$

$\sf{ = ( {2}^{20 - 15} )}$

$\sf{ = ( {2}^{5} )}$

$\sf{ = 32}$

Laws of exponents

$\sf {a}^{m} \times {a}^{n} = {a}^{m + n} \: \: \: \: \: \: \: \: \: \: \sf {a}^{m} \div {a}^{n} = {a}^{m - n} \\ \sf{( {a}^{m} ) ^{n} = {a}^{mn} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: a {}^{m} \times {n}^{m} = (ab) ^{m} } \\ \sf{a}^{0} = 1 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: {\frac{ {a}^{m} }{ {b}^{m} }= \left( \frac{a}{b} \right) ^{m} }$