what is the answer to: evaluate 101 raised to power 3
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Write the expression as,
101^3=(100+1)^3
Using algebraic identity,
(a+b)^3=a^3+b^3+3a^2b+3ab^2
Here, a=100 and b=1
Substitute the values,
(100+1)^3=(100)^3+1^3+3(100)^2(1)+3(100)(1)^2
(100+1)^3=1000000+1+30000+300
(100+1)^3=1030301
Therefore, (100+1)^3=1030301
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