Question

what is the answer to this question?

Answer 1

Answer:

(c) tan 60°

Step-by-step explanation:

We know that,

$\rm \tan 30^{\circ} = \dfrac{1}{\sqrt{3}}$

$\tt \dfrac{2 \tan 30^{\circ} }{1- \tan ^2 30^{\circ}}$

$\tt \implies \dfrac{2 \bigg( \dfrac{1}{ \sqrt{3} } \bigg)}{1 - \dfrac{1}{3} }$

$\tt \implies \dfrac{ \dfrac{2}{ \sqrt{3} } }{ \dfrac{3 - 1}{3} }$

$\tt \implies \dfrac{ \dfrac{2}{ \sqrt{3} } }{ \dfrac{2}{3} }$

$\tt \implies \dfrac{ \dfrac{\cancel{2}}{ \sqrt{3} } }{ \dfrac{\cancel{2}}{3} }$

$\tt \implies \dfrac{3}{\sqrt{3}}$

$\tt \implies \sqrt{3}$

$\tt \implies \tan 60^{\circ}$