Question

What is the answer?
What is the remainder?

Answer 1

Answer:

the answer of this questions is

2x-4

remainder is x+17

Hope it helps you....

Thank you...

Answer 2

⠀⠀⠀⠀Polynomial Division

$\boxed{\begin{array}{l | n | r}\sf 2x+3 &\sf 4x^2-3x+5&\sf2x-4\\ &\sf4x^2+6x\\ & ( - )\:\:( - )\\&\rule{60}{0.8}\quad\:\:\:\\&\sf\qquad-9x+5\\ &\sf\qquad-8x-12\\ &\qquad(+)\:\:( + )\\&\quad\rule{65}{0.8}\\&\qquad\sf-x+17\end{array}}$

$\rule{100}{0.8}$

☯ $\underline{\textsf{According to the Question :}}$

$:\implies\tt Dividend=Divisor \times Quotient +Remainder\\\\\\:\implies\tt 4x^2-3x+5=\bigg\lgroup(2x+3) \times (2x-4)\bigg\rgroup+(-\:x+17)\\\\\\:\implies\tt 4x^2-3x+5=\bigg\lgroup(2x+3) \times (2x-4)\bigg\rgroup+(17 - x)\\\\{\scriptsize\qquad\bf{\dag}\:\:\textsf{In Case, we want to check it.}}\\\\:\implies\tt 4x^2 - 3x + 5 = \bigg\lgroup2x(2x - 4) + 3(2x - 4)\bigg\rgroup + 17 - x\\\\\\:\implies\tt 4x^2 - 3x + 5 = 4x^2 - 8x + 6x - 12 + 17 - x\\\\\\:\implies\underline{\boxed{\textsf{ \textbf{4x ^\text2 - 3x + 5 = 4x ^\text2 - 3x + 5}}}}$

⠀

$\therefore\:\underline{\textsf{Hence, Remainder Obtained will be \textbf{(17 - x)}}}.$