Question

What is the Answer with explanation

Answer 1

Answer:

am is staright line so AMC is right angle

Answer 2

$\huge{\mathcal{\underline{\red{AnSWer}}}}$

Given : ABCDE is a regular pentagon

. The bisector ∠A of the pentagon meets the side CD at point M.

To prove : ∠AMC = 90°

Proof: We know that, the measure of each interior

angle of a regular pentagon is 108°.

∠BAM = 1/2 X 108° = 54°

Since, we know that the sum of a quadrilateral is 360°

In quadrilateral ABCM,

we have ∠BAM + ∠ABC + ∠BCM + ∠AMC = 360°

54° + 108° + 108° + ∠AMC = 360°

∠AMC = 360° – 270°

∠AMC = 90°

hence proved