Question

what is the Ap of the 0.6,1.7,2.8,.......to100 terms​

Answer 1

Answer:

Final term(100th term)=109.5

Step-by-step explanation:

Here, a=0.6, n=100, d=1.1

$t_{100}$=a+(n-1)d

    =0.6+(100-1)1.1

    =0.6+99 X 1.1

    =0.6+108.9

    =109.5