Question

What is the apparent position of an object below a rectangular block of glass 6 cm thick if a layer
of water 4 cm thick is on top of the glass? [Refractive index of glass and water =1.5 and 1.33
respectively]​

Answer 1

Explanation:

here we can use the formula ,

μ=real depththickness of the object/apparent depth

Now due to refraction at two different boundaries the apparent depth of the object is,

Apparent depth =thickness of glassμglass+thickness of waterμwater =61⋅5+41⋅3=3+4 =7 cm

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