Question

What is the approximate area of sector ABC with central angle Θ≈56°? Round your answer to the nearest tenth.

Answer 1

Answer:

68 sq.cm

Step-by-step explanation:

area of the sector[ABC]=πr2 [central angle/360]

area of sector=3.14*144[56/360]

=452.16[7/45]

=452.16 *0.15

=67.82 which is similar to 68

=68 sq· cm

Answer 2

Answer:

70.4 square cm.

Explaination:

$area \: of \: sector \: = \pi \times {r}^{2} \times \alpha \div 360^{o} \\ where \: \alpha \: is \: angle \: of \: sector$

= (22/7)×(12)^2×56/360

= (22/7)×12×12×(7/45)

= 22×12×12/45

= 22×16/5

= 352/5

= 70.4 sq. cm