What is the approximate linear speed (in km/hr) of a point at
the equator and pole due to motion of earth about its own
axis if the radius of the earth is 6400 km?
Answers
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Explanation:
Time period of rotation of earth,T = 24h
Radius Of the earth, R = 64,00 km
As v = R and 2π/T,
v= 2πR/T = [2×3.14×6400/24] km/h
Answer. = 1675km/h.
I hope it is helpful For you.
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