Question

what is the approximate molarity of pure water at 25 degree C ?​

Answer 1

Answer:

Just like there's a real molar concentration for water by itself ( 55.348 M ), there is a real molality for water by itself ( 55.510 m ). Let's say you had 1 L of water. At 25∘C , the density of water is 0.9970749 g/mL , so that's 0.9970749 kg .

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Answer 2

Explanation:

We were requested to compute the morality and polarity of pure water using the density of water at 25 degrees Celsius in this challenge. We may first determine the polarity at this temperature by taking your density and manipulating our units. We know that there is one Miller leader for every one centimetre cube, as well as 1000 millilitres and each leader. The molar mass of water can then be used to move from grammes of water to two moles of water. So, based on this calculation, the polarity of the solution is 55.3 Moeller. We can determine the morality by starting with our completed city and counting how many grammes of water and one leader we have.

So, once again, we know that there is one mil a leader in every centimetre cube and one leader in 1000 millilitres. As a result, we discover that one leader has 997 grammes of water. We can divide by the molar mass to get moles of water now that we know where grammes of water are, and we get 55 0.3 to 7 rolls of water. We divide moles by kilogrammes in our solution to calculate morality. So we'll divide our moles of water (which we just calculated) by the enormous water (which we determined above). By dividing by 1000, we can convert grammes to kilos and arrange the Dominator. When we do so, we discover that our morality is 55.5 percent.