What is the approximate value of the variance of the dataset 4,2,5,8,6?
Answers
Answered by
0
Answer:
4
Step-by-step explanation:
mean (M)=4+2+5+8+6/5=25/5=5
variance (sigma square)=(4-5)^2+(2-5)^2+(5_5)^2+(8-5)^2+(6-5)^2/5
=1+9+0+9+1/5=20/5=4
Answered by
0
Answer:
4
Step-by-step explanation:
Mean (M) =4+2+5+8+6/5
=25/5
=5
Variance=(4-5)²+(2-5)²+(5-5)²+(8-5)²+(6-5)²/5
=1+9+0+9+1/5
=20/5
=4 (Answer)
Similar questions