Math, asked by rishabjaral5158, 1 month ago

What is the approximate value of the variance of the dataset 4,2,5,8,6?

Answers

Answered by ramanjal6677
0

Answer:

4

Step-by-step explanation:

mean (M)=4+2+5+8+6/5=25/5=5

variance (sigma square)=(4-5)^2+(2-5)^2+(5_5)^2+(8-5)^2+(6-5)^2/5

=1+9+0+9+1/5=20/5=4

Answered by minatisoren50
0

Answer:

4

Step-by-step explanation:

Mean (M) =4+2+5+8+6/5

=25/5

=5

Variance=(4-5)²+(2-5)²+(5-5)²+(8-5)²+(6-5)²/5

=1+9+0+9+1/5

=20/5

=4 (Answer)

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