what is the are of a rectangle whose diagonal is 12cm and breadth is 3cm And pls explain
Answers
Answered by
3
Step-by-step explanation:
length of rec=4cm
Breadth of rec=3cm
diagonal of rec=√(l)2+(b)2
diagonal of rec=√(4)2+(3)2
= √16+9
=√25
=5cm
Answered by
1
Let us name the width a and the length b
We have the given:
a^2 +b^2= 12
2a+2b =3
We can write them as
a^2+b^2+2ab-2ab=12
a+b=3/2
Then
(a+b) ^2 - 2ab=12
a+b=3/2
Then substitute the second equation in the first one :
(3/2)^2 - 2ab=12
Implies: 9/4 - 2ab=12
Imlpies: - 2ab=12-9/4
Implies: - 2ab=(48-9)/4
Implies: - 2ab=39/4
Thus ab=-39/8
But the area can't be in negative, i guess there is a mistake in the given numbers
Step-by-step explanation:
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