Question

what is the are of a rectangle whose diagonal is 12cm and breadth is 3cm And pls explain

Answer 1

Step-by-step explanation:

length of rec=4cm

Breadth of rec=3cm

diagonal of rec=√(l)2+(b)2

diagonal of rec=√(4)2+(3)2

= √16+9

=√25

=5cm

Answer 2

Let us name the width a and the length b

We have the given:

a^2 +b^2= 12

2a+2b =3

We can write them as

a^2+b^2+2ab-2ab=12

a+b=3/2

Then

(a+b) ^2 - 2ab=12

a+b=3/2

Then substitute the second equation in the first one :

(3/2)^2 - 2ab=12

Implies: 9/4 - 2ab=12

Imlpies: - 2ab=12-9/4

Implies: - 2ab=(48-9)/4

Implies: - 2ab=39/4

Thus ab=-39/8

But the area can't be in negative, i guess there is a mistake in the given numbers

Step-by-step explanation: