Question

what is the area a rhombus
whose diagonals are
of lengths
10 cm and 8.2cm?
2.
24 cm²​

Answer 1

Answer:

Step-by-step explanation:

area=diagnol×length÷2

=10×8.2÷2

=82÷2

=41cm2

hope u understand and if not go once again!!!

Answer 2

$\boxed{\fbox{SOLUTION}}$

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⇒ $Area of rhombus : \frac{1}{2} d_{1} d_{2}$

$\fbox{ NOTE : d is for diagonal}$

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WE HAVE :

✔ Area of rhombus = $x$

✔ Length of $d_{1}$ = $10cm$

✔ length of $d_{2}$ = $8.2cm = \frac{82}{10}$

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⇒ $x = \frac{1}{2}\times10\times\frac{82}{10}$

⇒ $x = 41cm^{2}$

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THANKS

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