Question

. What is the area and perimeter of a rectangle having length of 19 cm and breadth of 10cm?

Answer 1

Given

• length 19 cm
• width 10 cm

To find

• area of rectangle
• perimeter of rectangle

solution

area of rectangle l×b

=19×10

=190 square cm.

.

perimeter of rectangle

2( l+b)

2(19+10)

2(29)

=58 cm

hence the perimeter of rectangle is 58 cm

and area of rectangle is 190 square cm

Thanks

Hope its helpful

Answer 2

$\huge\fbox\red{Ex}\fbox\pink{pl}\fbox\purple{An}\fbox\green{Na}\fbox\blue{ti}\fbox\orange{oN}$

$\Large{\underline{\underline{\sf{Given:}}}}$

$\small \mathfrak \blue{Breadth \: of \: rectangle = 1 0 \: cm }$

$\small \mathfrak \blue{Length \: of \: rectangle = 19 \: cm }$

$\Large{\underline{\underline{\sf{Find:}}}}$

$\small \mathfrak \blue{Area \: of \: rectangle }$

$\small \mathfrak \blue{Perimeter \: of \: rectangle}$

$\Large{\underline{\underline{\sf{Solution:}}}}$

$\small \mathfrak \pink{Area \: of \: rectangle = \red{ length × breadth}}$

$\longmapsto \small \mathfrak \blue{ \: \: \: \: \: \: \: \: = \: 19 \: cm \: \times 10cm }$

$\longmapsto \small \mathfrak \blue{ \: \: \: \: \: \: \: \: = \: 190 \: cm { }^{2} }$

$\small \mathfrak \pink{Perimeter \: of \: rectangle \: = \red{2 ( length + breadth)}}$

$\longmapsto \small \mathfrak \blue{ \: \: \: \: \: \: \: \: = 2(19cm \: + 10cm) }$

$\longmapsto \small \mathfrak \blue{ \: \: \: \: \: \: \: \: = 38cm \: + 20cm }$

$\longmapsto \small \mathfrak \blue{ \: \: \: \: \: \: \: \: = 58 \: cm}$

$\large \mathfrak \green{Therefore}$

$\small \mathfrak {Area \: of \: rectangle = 190 \: cm \: {}^{2} }$

$\small \mathfrak {Perimeter \: of \: rectangle \: = 58 \: cm}$