Question

What is the area common to the circles r a and r 2a cos θ?

Answer 1

here is ur answer..hope this helps

Answer 2

Abscissa Value is $rcos\theta$

Step-by-step explanation:

Given value of r = a  

• It's the circle $x^2+y^2=a^2$

$r=2acos\theta$

$r^2=2a(rcos\theta)$

$x^2+y^2=2ax$ which on solving gives

$(4\pi-33-\sqrt 6)a^2$

Using $x^2+y^2=2ax$

( ∵$rcos(\theta)$ is the abscissa of any point with respect to some value of $\theta$)

⟹ $(x-a)^2+y^2=a^2$

Which is a circle centered at (a,0) having the same the radius.

When a = 5 then refer figure.