What is the area (in square units) of the triangular region enclosed by the graphs of the equations x+y=3, 2x+5y=12 and the x-axis ?
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3 Sq units id the area of triangular region enclosed by the graphs of the equations x+y=3, 2x+5y=12 and the x-axis
Step-by-step explanation:
x+y=3 Eq1
2x+5y=12 Eq2
x -axis => y = 0 Eq3
Eq1 & Eq3
=> x = 3 , y = 0
(3,0)
Eq2 & Eq3
=> x = 6 , y = 0
(6 , 0)
Eq1 & Eq2
x = 1 & y = 2
(1 ,2 )
Vertices of triangle are (3 , 0) , (6 , 0) & (1,2)
Area = (1/2) | 3(0 - 2) + 6(2 - 0) + 1(0-0) |
= (1/2) | -6 + 12 + 0|
= (1/2) | 6 |
= 3
3 Sq units id the area of triangular region enclosed by the graphs of the equations x+y=3, 2x+5y=12 and the x-axis
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