Question

What is the area of a circle whose circumference is 1188 meters?

Answer 1

hi friend
here's your answer looking for

circumference of circle = 2πr

$1188 = 2 \times \frac{22}{7} \times r \\ \\ \frac{1188 \times 7}{44} = r \\ \\ r = 189m$
now,

area of circle =
$\pi \: {r}^{2} \\ \\ \frac{22}{7} \times 189 \times 189 \\ \\ = 112266 {m}^{2}$
so this is your answer

hope you are satisfied with my answer

Answer 2

Answer:

112311.187 ≈ 112311 $m^{2}$

Step-by-step explanation:

Given:- Circumference of the circle = 1188 meters.

To Find:- Area of the circle.

Solution:-

As we know, Circumference of a circle = 2πr, where r = radius of circle.

So, 2πr = 1188

⇒ r = 1188/2π

      = 594/π

As we know, Area of a circle = $\pi r^{2}$

⇒ Area = $\pi (\frac{594}{\pi } )^{2}$

            = $\frac{(594)^{2} }{\pi }$

            = 112311.187 $m^{2}$.

#SPJ2