Question

What is the area of a quadrant of a circle whose circumference is 44 cm *
4 points
77/2 cm sq
77/8 cm sq
77/ 9 cm sq​

Answer 1

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Given circumference of circle= 44cm

Circumference= $2\pi r$

$= > 2\pi r = 44$

$= > 2 \times \frac{22}{7} \times r = 44$

$\sf = > \frac{44}{7} r = 44$

$\sf = > r = \frac{44 \times 7}{44}$

$\sf = > r = 7cm$

Now area= $\pi {r}^{2}$

$= > \frac{22}{7} \times {7}^{2} = 154$

So area of circle is $154c {m}^{2}$

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