Math, asked by sandy73201, 3 months ago

What is the area of a rectangle whos legth is 8/10 m and width is 2/3 m

Answers

Answered by harishri30
1

Answer:

8/15 or 0.534

Step-by-step explanation:

Area of rectangle= length × breadth

= 8/10 × 2/3

= 8/15

Answered by Anonymous
107

Given:-

  • Length = \sf{\dfrac{8}{10} \:m}

  • Width = \sf{\dfrac{2}{3} \:m}

To Find:-

  • Area of rectangle.

Solution:-

\large\boxed{\underline{{\sf Area=width\times length  }}}

\pink{\implies\:\:} \sf{A=\dfrac{2}{3} \times \dfrac{8}{10} }

\pink{\implies\:\:} \sf{A=\dfrac{2\times8}{3\times10} }

\pink{\implies\:\:} \sf{A=\dfrac{16}{30} }

\pink{\implies\:\:} \sf{A=\dfrac{16 \div 2}{30 \div 2} }

\pink{\implies\:\:} \sf{A=\dfrac{8}{15} }

\large\boxed{\underline{\purple{\sf\therefore\: Area=\dfrac{8}{15}   }}}

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