Question

What is the area of a rectangle whose length is twice its width and whose perimeter is equal to that of a square whose area is 1?
a) 1
b) 6
c) 2/3
d)8/9​

Answer 1

Answer:

Hi the answer is 8/9Let l be the length of the rectangle and w be the width of the rectangle

Give l = 2w

Perimeter of this rectangle = 2w + w + 2w + w = 6w

Perimeter is equal to the perimeter of a square whose area is 1

side of a square whose area is 1 = 1√1 = 1

perimeter of a square whose side is 1 = 4∗14∗1 = 4

=> Perimeter of this rectangle = 6w = 4

=> w = 2323

=> l = 2∗23=432∗23=43

Area of the rectangle = l * w =4/3×2/3=8/9.This is the answer.

Answer 2

Answer:

c

Explanation:

am smart