Question

What is the area of a rectangle with length 20 cm and breadth 15 cm?
1) 200 sq cm
2) 300 sq cm
3) 400 sq cm ​

Answer 1

Solution -

Here , we have to find the area of a rectangle which has its length as 20 cm and breadth as 15 cm respectively .

$\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(5,0){2}{\line(0,1){3}}\multiput(0,0)(0,3){2}{\line(1,0){5}}\put(0.03,0.02){\framebox(0.25,0.25)}\put(0.03,2.75){\framebox(0.25,0.25)}\put(4.74,2.75){\framebox(0.25,0.25)}\put(4.74,0.02){\framebox(0.25,0.25)}\multiput(2.1,-0.7)(0,4.2){2}{\sf\large 20 cm}\multiput(-1.4,1.4)(6.8,0){2}{\sf\large 15 cm}\put(-0.5,-0.4){\bf A}\put(-0.5,3.2){\bf D}\put(5.3,-0.4){\bf B}\put(5.3,3.2){\bf C}\end{picture}$

Area of the rectangle -

> Length × Breadth

> 20 cm × 15 cm

> 300 cm² or 300 square cm .

Hence , option 2 is the correct answer.

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Additional Information -

$\begin{array}{|c|c|c|}\cline{1-3}\bf Shape&\bf Volume\ formula&\bf Surface\ area formula\\\cline{1-3}\sf Cube&\tt l^3}&\tt 6l^2\\\cline{1-3}\sf Cuboid&\tt lbh&\tt 2(lb+bh+lh)\\\cline{1-3}\sf Cylinder&\tt {\pi}r^2h&\tt 2\pi{r}(r+h)\\\cline{1-3}\sf Hollow\ cylinder&\tt \pi{h}(R^2-r^2)&\tt 2\pi{rh}+2\pi{Rh}+2\pi(R^2-r^2)\\\cline{1-3}\sf Cone&\tt 1/3\ \pi{r^2}h&\tt \pi{r}(r+s)\\\cline{1-3}\sf Sphere&\tt 4/3\ \pi{r}^3&\tt 4\pi{r}^2\\\cline{1-3}\sf Hemisphere&\tt 2/3\ \pi{r^3}&\tt 3\pi{r}^2\\\cline{1-3}\end{array}$

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Answer 2

Answer:

Given :-

Length = 20 cm

Breadth = 15 cm

To Find :-

Area

Solution :-

We know that

Area of rectangle = l × b

l = length

b = breadth

Area = 20 × 15

Area = 300

Hence,

Area of rectangle is 300 cm²