Question

what is the area of a rectangular
$▭$ plot whose one side is 8m long and diagonal is of length 17m.
$\purple{\boxed{\tt{Don't\:spam}}}$​

Answer 1

$\purple{\boxed{\tt{Given࿐}}}$

• Shape = Rectangle
• Diagonal of Rectangle = 17m
• Length of the Rectangle = 8m

$\red{\boxed{\tt{To \:Find :-}}}$

• The Area of the Rectangle

$\purple{\boxed{\tt{Solution :-}}}$

$\pink{\boxed{\bf{❏ Using\: Pythagoras\: Theorem}}}$

➞ (Diagonal)² = (Length)² + (Breadth)²

➞ ( 17 )² = ( 8 )² + (Breadth)²

➞ 289 = 64 + (Breadth)²

➞ 289 - 64 = (Breadth)²

➞ 225 = (Breadth)²

➞ √225 = Breadth

$\purple{\boxed{\tt{➞ 15m =Breadth}}}$

________________

$\red{\boxed{\bf{❏ Using\: Area \:of \:Rectangle}}}$

⟾Area of Rectangle= length×breadth

⟾ Area of Rectangle = 17 × 15

⟾ Area of Rectangle = 255m²

Therefore, Area of Rectangle = 255m²

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$\blue{\underbrace{\tt{★ Additional \:Info :}}}$

$\red{\bf{Formulas \:Related\: to\: Rectangle :}}$

• Perimeter of Rectangle = 2( l + b)
• Area = Length × Breadth
• Length = Area / Breadth
• Breadth = Area / Length
• Diagonal = √(l)² + (b)²

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Answer 2

Given࿐

Shape = Rectangle

Diagonal of Rectangle = 17m

Length of the Rectangle = 8m

ToFind:−

The Area of the Rectangle

Solution:−

➞ (Diagonal)² = (Length)² + (Breadth)²

➞ ( 17 )² = ( 8 )² + (Breadth)²

➞ 289 = 64 + (Breadth)²

➞ 289 - 64 = (Breadth)²

➞ 225 = (Breadth)²

➞ √225 = Breadth

________________

⟾Area of Rectangle= length×breadth

⟾ Area of Rectangle = 17 × 15

⟾ Area of Rectangle = 255m²

Therefore, Area of Rectangle = 255m²

________________

}}Formulas Related to Rectangle:

Perimeter of Rectangle = 2( l + b)

Area = Length × Breadth

Length = Area / Breadth

Breadth = Area / Length

Diagonal = √(l)² + (b)²

________________