Question

what is the area of a shape enclosed by lines x+4=0 and x=0 and a circle (x+2)^2+(y-3)^2=20

Answer 1

Answer

Here x

2

+y

2

=16

∴y

2

=16−x

2

y=

4

2

−x

2

Area =

0

∫

π/2

4

2

−x

2

dx

=[

2

x(

4

2

−x

2

)

+

2

4

2

sin

−1

(

4

π

)]

0

π/2

=(

2

4(0)

+

2

16

sin

−1

(1))−(0+

2

16

sin

−1

(0))

=0+8(

2

π

)−0

∴ Required area =4π