what is the area of a square whose perimeter is (4a + 12b) units
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Answered by
1
Answer:
Step-by-step explanation:
side of square =(4a+12b)/4= a+3b
so area = (a+3b)^2
=a^2+9b^2+6ab
Answered by
0
Step-by-step explanation:
perimeter of square is 4 into sides
therefore 4 × (4a + 12b)
16a + 48b units
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