Question

what is the area of a trapezium whose parallel sides are 12 cm and 16 cm and whose height us equal to that of equilateral triangle of side√3​

Answer 1

Answer:

hey here is your answer in above Attachments

pls mark it as brainliest

for finding altitude of equilateral triangle u can also use 30-60-90 degree property

Answer 2

Given : Trapezium whose parallel sides are 12 cm and 16 cm and whose height is equal to that of equilateral triangle of side√3​.

To Find : Area of trapezium

Solution :

Trapezium is a shape with four sides in which one set of two opposite sides are parallel and other set are not parallel.

Area of trapezium is given by : $\frac{1}{2}$ ×(sum of two parallel sides) × (Distance between them)

Equilateral triangle is a triangle with all sides are equal and angles are 60°.

Height of equilateral triangle is : $\frac{\sqrt{3} }{2} a$ where a is side length

a = $\sqrt{3}$ cm

Therefore, height of trapezium : $\frac{\sqrt{3} }{2}$ × √3 = $\frac{3}{2}$

Therefore, area of trapezium =

= $\frac{1}{2}$ × (12 + 16) × $\frac{3}{2}$

= $\frac{1}{2}$ × 28 × $\frac{3}{2}$

= 7 × 3

= 21 $cm^{2}$

Therefore, Area of trapezium is 21 $cm^{2}$.