Question

what is the area of a triangle 14 cm 10 cm 20 cm

Answer 1

Answer:

Step-by-step explanation:

Area=√(s(s-a)(s-b)(s-c))

s=14+10+20/2

s=22

Area=√(22*8*12*2)

Area=8√66cm²

Answer 2

a = 20cm

b = 14cm

c = 10cm

We know that,

Area of triangle =

$\sqrt{s(s - a)(s - b)(s - c)}$

In which,

$s = \frac{a + b + c}{2}$

According to question

$s = \frac{20 + 10 + 14}{2}$

$s = \frac{44}{2}$

$s = 22cm$

$area \: of \: triangle = \sqrt{22(22 - 20)(22 - 14)(22 - 10)}$

$= \sqrt{22 \times 2 \times 12 \times 8}$

$= \sqrt{11 \times 2 \times 2 \times 2 \times 3 \times 2 \times 2 \times 2}$

$= 2 \times 2 \times 2 \sqrt{11 \times 3}$

$= 8 \sqrt{33}$

So area of triangle is 8√33