Question

What is the area of a triangle if its base is 4.8 cm.
and height is 3.6 cm?​

Answer 1

Given:

• The base of the triangle is 4.8 cm
• The height of the triangle is 3.6 cm

To find:

• The area of the triangle

When the base and height of the triangle is given, the formula to find the area of the triangle is = $\boxed{\bf \frac{1}{2}\times base \times height}\ unit\ sq.$

Now,

Area of the triangle = ¹/₂ × 4.8 × 3.6

Area of the triangle = 8.64 cm sq.

Hence

The area of the triangle is 8.64 cm sq

More Information:

When the sides of the triangle will be given and the area is asked then we use Heron's formula

$Area = \sqrt{S(S-a)(S-b)(S-c)}$

In which

• S = Semiperimeter of the triangle. i.e. (periemter/2)
• 'a', 'b', and 'c' are the sides of the triangle.

Answer 2

Answer:

$\Huge {\mathbf {\color{navy}{Ans}{\red{wer}}}}$

$\small {\mathbf {\color{blue}{Given \: base \: of \: triangle \:}}  =}{\mathbf {\color{red}{ \: \: 4.8cm}}}$

$\small {\mathbf {\color{blue}{height \: of \: triangle \: }}=}{\mathbf {\color{red}{ \: 3.6cm }}}$

$\small {\boxed {\bf \color{plum}{area =  \frac{1}{2} ∣base×height∣}}}$

$\small \bf \green{= \frac{1}{2} ×4.8×3.6=2.4×3.6}$

$\small {\boxed {\bold {\color{orange}{area = 8.64 {cm}^{2} }}}}$