Question

What is the area of a triangle whose base is 18.2 cm and height is 9 cm​

Answer 1

Answer:

Hello!!

Here is ur answer-

Base of the triangle = 18.2cm

Height of the triangle = 9 cm

Area of the triangle = 1/2 × b × h

= 1/2 × 18.2 × 9

= 9.1 × 9

= 81.9

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Thank you!!

Regards,

Sri Nithya

9th class

Answer 2

Given :

• Base of Triangle is 18.2 cm .
• Height of Triangle is 9 cm .

To Find :

• Area of Triangle.

Formula Used :

• Area of Triangle = ½ × Base × Height

Here ,

• Base of Triangle is 18.2 cm .
• Height of Triangle is 9 cm .

⠀⠀⠀⠀⠀⠀$\underline {\frak{\star\:Now \: By \: Substituting \: the \: Given \: Values \::}}$

• Area = ½ × 18.2 × 9
• Area = 18.2 × 4.5
• Area = 81.9 cm²

Hence , Area of Triangle is 81.9 cm²

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$\large {\boxed{\sf{\mid{\overline {\underline {\star More\:To\:know\::}}}\mid}}}$

$\begin{gathered}\boxed{\begin {array}{cc}\\ \dag\quad \Large\underline{\bf Formulas\:of\:Areas:-}\\ \\ \star\sf Square=(side)^2\\ \\ \star\sf Rectangle=Length\times Breadth \\\\ \star\sf Triangle=\dfrac{1}{2}\times Breadth\times Height \\\\ \star \sf Scalene\triangle=\sqrt {s (s-a)(s-b)(s-c)}\\ \\ \star \sf Rhombus =\dfrac {1}{2}\times d_1\times d_2 \\\\ \star\sf Rhombus =\:\dfrac {1}{2}p\sqrt {4a^2-p^2}\\ \\ \star\sf Parallelogram =Breadth\times Height\\\\ \star\sf Trapezium =\dfrac {1}{2}(a+b)\times Height \\ \\ \star\sf Equilateral\:Triangle=\dfrac {\sqrt{3}}{4}(side)^2\end {array}}\end{gathered}$

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