What is the area of a triangle, whose one altitude is 10cm and length of base is equal to the side of a cube having volume of 1331cm³
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Answer:
Area of Δ = 55 cm²
Given:
Altitude of Δ = 10cm
Volume of Cube = 1331cm³
Step-by-step explanation:
► To find the side of the Cube
Volume Given = 1331cm³
- Formula for Volume of Cube → side³
According to the Question:
→ side³ = 1331
⇒ side = ∛1331 = 11
∴ side of Cube = 11cm
As mentioned in the Question:
Base of Δ = side of Cube
∴ Base of Δ = 11cm
► To find the area of triangle
Altitude = Height = 10cm
Base = 11cm
- Area of Δ → 1/2 × base × height
⇒ 1/2 × 11 × 10
⇒ 10/2 × 11
⇒ 5 × 11 = 55
∴ Area of Δ = 55cm²
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