Question

What is the area of a triangle with a base of 4 inches and a height of 17 inches?​​

Answer 1

Answer:

The required area of the ∆:

$\boxed{ \rm{ar( \triangle) = 34 \: {inch.}^{2} }}$

Step-by-step explanation:

We have:

Base = 4 inches

Height = 17 inches

By using Formula, A = 1/2 * bh

⇒ ar(∆) = 1/2 × 4 × 17 inch²

⇒ ar(∆) = 2 × 17 inch²

⇒ ar(∆) = 34 inch²

Thus, The Area of Required ∆ is 34 inch².

More Explanation :

• Area of triangle = ½ × base × height .
• Perimeter of triangle = sum of sides .
• A triangle has 3 vertices.
• A triangle has 3 edges .
• Sum of all angles in a triangle is equal to 180⁰.
• A triangle has three sides and three angles .
• Internal angles is 60⁰.

Answer 2

Answer:

34 square inches

Step-by-step explanation:

A(triangle)=1/2×b×h. =1/2×17×4

=17×2

=34