Question

What is the area of a triangular park with sides 9m, 12m and 15m?

a) 54m2

b) 45 m2

c) 50 m2

d) 34 m2​

Answer 1

Answer:

If ABCD is a quadrilateral, 

AB=12m,BC=5m,CD=6m,DA=15m and ∠ABC=90o

Area of ABCD = Area of ΔABC+Area of ΔACD

In Δ ABC, ∠B=90o

Therefore, AC2=AB2+BC2=122+52

So, AC=13

Area of Δ ABC = 21×AB×AC=21×12×5=30m2

In ΔACD, s = 26+15+13 = 17m

Applying Heron's formula,

Area of ΔACD = S(S−a)(S−b)(S−c) = 17(17−13)(17−15)(17−6)

                          = 17(4)(2)(11)=2374

Hence, Area of quadrilateral ABCD =30+2374

So, option C is correct

Answer 2

Answer:

ans. 54 m2

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