Question

What is the area of a triangular park with sides 9m, 12m and 15m?

a) 54m2

b) 45 m2

c) 50 m2

d) 34 m2​

Answer 1

Answer:

its option a.

54 m2

the formula used to find thearea of triangle is 1/2 X base X height

Step-by-step explanation:

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Answer 2

Answer:

54 m² is the area of a triangular park.

Explanation

• 9m, 12m, 15m

As we know that,

We can find area of the triangle using Heron's Formula as;

$\circ \: \: \: {\boxed{\tt\red{ Area_{( \Delta )} = \sqrt{ s(s-a)(s-b)(s-c) } }}}$

Where as

• s = (a+b+c)/2
• a, b, c = Sides

${\tt{ s = \dfrac{a+b+c}{2} }} \\ \\ \colon\leadsto{\tt{ s = \dfrac{9+12+15}{2} }} \\ \\ \colon\leadsto{\tt{ s = \dfrac{ \cancel{36} }{ \cancel{2} } }} \\ \\ \colon\leadsto{\tt{ s = 18 }}$

According to Question,

putting values,

${\tt{ Area_ { \Delta } = \sqrt{ 18(18-9)(18-12)(18-15) } }} \\ \\ \\ \colon\implies{\tt{ Area_ { \Delta } = \sqrt{ 18 \times 9 \times 6 \times 3 } }} \\ \\ \\ \colon\implies{\tt{ Area_ { \Delta } = \sqrt{2916} }} \\ \\ \\ \colon\implies{\boxed{\tt\orange{ Area_ { \Delta } = 54 \ m^2 }}}$

Hence,

• The Area of the triangular park is 54 m² .

a) Option is correct!!

More to Know:

• Area = ½ × base × Height
• Perimeter = a+b+c
• a+b+c/2 = s