Math, asked by akbcaterings, 9 months ago

What is the area of a trianle whose sides are 18,10,14

Answers

Answered by Pragya3918red
0

Step-by-step explanation:

Semi - perimeter = (18 + 10 + 14)/2 units

= 42/2 units

= 21 units

Area = √{21 × (21 - 18) × (21 - 10) × (21 - 14)} sq.units

= √(21 × 3 × 11 × 7) sq.units

= 21√11 sq.units

HOPE THIS ANSWER WILL HELP YOU.

MARK ME THE BRAINLIEST.

Answered by vaibhavkatiyar443
0

Answer:

preimeter=18+10+14=42

semiperimeter= 42/2= 21

√21(21-18)(21-10)(21-14)

√21*3*11*7=4851 is area

Similar questions