What is the area of an equilateral triangle having side-length as 10√3 cm
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Step-by-step explanation:
area of equilateral triangle =√3×side2/4
√3×10√3×10√3/4=
25√3 cm2
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Solution :-
Given ,
- Side of triangle = 10√3 cm
- Type of triangle :- Equilateral triangle
We need to find ,
- Area of triangle = ?
As we know that ,
Area of Equilateral triangle = √3/4 a²
Where , ‘a’ is side of triangle = 10√3 cm
⇒ Area of ∆ = √3/4 × ( 10√3 )²
⇒ Area of ∆ = √3/4 × [ 100(3) ]
⇒ Area of ∆ = √3/4 × 300
⇒ Area of ∆ = √3 × 75
⇒ Area of ∆ = 75√3 cm²
Hence , area of the Equilateral ∆ = 75√3 cm²
More information :-
- Area of ∆ = 1/2 × base × height
- Area of square = side²
- Area of rectangle = l × b
- Perimeter of rectangle = 2(l + b)
- Perimeter of square = 4 × side
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