what is the area of an equilateral triangle that has an altitude of 9?
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use pythagoras theorem
9*9=a*a-a/2*a/2
81 = 3a*a/4
324= 3a*a
108=a*a
sqrt(108)=a
10.392=a
9*9=a*a-a/2*a/2
81 = 3a*a/4
324= 3a*a
108=a*a
sqrt(108)=a
10.392=a
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