Question

what is the area of Canvas required to make a conical surface tent with height 5 M and radius of base = 12 m​

Answer 1

Hello!

If height = 5 m

Radius = 12 m

Then slant height = √5² + 12²

l = 13 m

Surface area of canvas = πRL

= 22/7 × 12 × 13

$= \frac{22}{7} \times 12 \times 13 = \frac{22 \times 12 \times 13}{7} m {}^{2}$