Math, asked by tannubindal7983, 5 months ago

what is the area of isosceles right angle triangle with equal sides measure 10m​

Answers

Answered by Afifur50
0

Answer:

Given that 10 cm is the length of the equal sides. Therefore area of the triangle = ½×a² = ½×10² = ½×10×10 = ½×100 = 50 cm.

Answered by honeyhd10
0

Answer:

34.1 cm

Step-by-step explanation:

Let ,  

Length of each of the equal sides of the isosceles right-angled triangle = a = 10 cm  

 Base = Height = a

Area of isosceles right – angled triangle = 1/2 x Base x Height

The hypotenuse of an isosceles right – angled triangle can be obtained using Pythagoras’ theorem  

If h denotes the hypotenuse, we have:

⇒ h²=a²+a²

⇒ h=2a²

⇒ h=√2a

as side=10cm

⇒ h=10√2 cm

perimeter of isosceles right angled triangle=2a+√2a

⇒ 2×10+1.41×10

⇒ 20+14.1

⇒ 34.1 cm.

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