what is the area of isosceles right angle triangle with equal sides measure 10m
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Answer:
Given that 10 cm is the length of the equal sides. Therefore area of the triangle = ½×a² = ½×10² = ½×10×10 = ½×100 = 50 cm.
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Answer:
34.1 cm
Step-by-step explanation:
Let ,
Length of each of the equal sides of the isosceles right-angled triangle = a = 10 cm
Base = Height = a
Area of isosceles right – angled triangle = 1/2 x Base x Height
The hypotenuse of an isosceles right – angled triangle can be obtained using Pythagoras’ theorem
If h denotes the hypotenuse, we have:
⇒ h²=a²+a²
⇒ h=2a²
⇒ h=√2a
as side=10cm
⇒ h=10√2 cm
perimeter of isosceles right angled triangle=2a+√2a
⇒ 2×10+1.41×10
⇒ 20+14.1
⇒ 34.1 cm.
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