Question

what is the area of parallelogram whose base and height are 14 cm and 8 cm respectivey

Answer 1

Answer :

• Area of parallelogram = 112cm²

Given :

• Base of parallelogram = 14cm
• Height of parallelogram = 8cm

To find :

• Area of parallelogram

Solution :

To find the Area of parallelogram we have to use the formula of area of parallelogram then we get answer of area of parallelogram

• Area of parallelogram = b × h

Where, b is base and h is height

⟶ Area of parallelogram = base × height

⟶ Area of parallelogram = 14 × 8

⟶ Area of parallelogram = 112 cm²

Hence , Area of parallelogram = 112cm².

More Explanation :

• Parallelogram has 4 sides
• Parallelogram has 4 vertices
• Perimeter of parallelogram = 2 × sum of adjacent sides length
• Area of parallelogram = base × height
• Quadrilateral is the type of polygon (Parallelogram)
• Parallelogram is a 2D shape
• Opposite sides are parallel
• Opposite angles are congruent
• Consecutive angles are supplementary
• There are a three types of parallelogram: rhombus, rectangle and square

Answer 2

$\large \frak \green{ \pmb{ \underline{Given : }}}$

• Base and height are 14 cm and 8 cm respectively.

$\large \frak \green{ \pmb{ \underline{ To \: find : }}}$

• Find the area of parallelogram.

$\large \frak \green{ \pmb{ \underline{Solution : }}}$

$\fbox{\sf\pink{ \underline{Area \: of \: parallelogram \: = \: Base \: × \: height}}}$

$\sf{ \qquad : \implies \: Area \: of \: parallelogram = 14 \times 8}$

$\sf{ \qquad : \implies \: Area \: of \: parallelogram \: = 112}$

$\boxed{ \sf { \underline \color{gray}{{ Area \: of \: parallelogram = 112 {cm}^{2} }}}}$